How do you factor #5(2-j)+(2j-3)#?

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Answer 1 · 2017-08-17T10:49:55

#(7 - 3j)#

#5(2 - j) + (2j - 3)#

Removing the brackets

#10 - 5j + 2j - 3#

Collect like terms

#-5j +2j +10 -3#

Note: If it's simplify, then you can just add them up together to get out the answer..

But since it's factors..

#(-5j +2j)+ (+10 -3)#

#(-5j +2j) (+7)#

#j (-5 + 2) +1(7)#

#j (-3) +1(7) -> "No Factor?"#

But can be simplified to #-> (7 - 3j)#