How do you factor $54 + 27t + 3t^2$ ?

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Answer 1 · 2015-05-28T00:17:35

$f(t) = 3(t^2 + 9t + 18) = 3(t - p)(t - q)$

Find p and q by composing factor pairs of $18$ : $(1, 18);(2, 9);(3, 6)$ .

$p = 3$ and $q = 6$ .

$f(x) = 3[(t + 3)(t + 6)]$

Answer 2 · 2015-05-28T03:46:25

Answer: $3t^2+27t+54=3(t+3)(t+6)$

Problem: Factor $54+27t+3t^2$ .

Rewrite the equation as $3t^2+27t+54$ .

Factor out the GCF $3$ .

$3(t^2+9t+18)$

Factor $(t^2+9t+18)$ by determining two factors of $18$ that when added equal $9$ .

The numbers $3$ and $6$ meet the requirement.

The factors for $3t^2+27t+54$ are $3(t+3)(t+6)$ .

How do you factor 54 + 27t + 3t^254 + 27t + 3t^2?