How do you factor #54a^4 - 16ab^3#?

1 Answer
Jul 5, 2016

Answer:

#2a(3a−2b)(9a^2+6ab+4b^2)#

Explanation:

Take out common factors from #54# and #16#.
The highest value that can be factored out is #2#.

So far:

#2(27a^4 - 8ab^3)#

Now lets take out common factors between the variables. The highest value that can be pulled out from #a^4# and #ab^3# is #a#.

#2a(27a^3 - 8b^3#)

We're not done yet.

#2a(3a−2b)(9a^2+6ab+4b^2)#