# How do you factor 54a^4 - 16ab^3?

Jul 5, 2016

2a(3a−2b)(9a^2+6ab+4b^2)

#### Explanation:

Take out common factors from $54$ and $16$.
The highest value that can be factored out is $2$.

So far:

$2 \left(27 {a}^{4} - 8 a {b}^{3}\right)$

Now lets take out common factors between the variables. The highest value that can be pulled out from ${a}^{4}$ and $a {b}^{3}$ is $a$.

2a(27a^3 - 8b^3)

We're not done yet.

2a(3a−2b)(9a^2+6ab+4b^2)