How do you factor #54c^3d^4+9c^4d^2#?

2 Answers
Jun 16, 2018

Answer:

#9c^3d^2(6d^2+c)#

Explanation:

We check it by expanding:
#9c^3d^2(6d^2+c)=54c^3d^4+9c^4d^2#

Aug 9, 2018

Answer:

#9c^3d^2(6d^2+c)#

Explanation:

Look at what power each #c# and #d# is raised to and take out the most that you can out of both of them:

there are at least three c's in both terms so you can pull out a #c^3# and there are at least 2 d's in both terms so pull out #d^2#. Finally there is a common factor 9 in both terms so we'll pull that out as well:

#9c^3d^2(6d^2+c)#