How do you factor $5x^2– 4x – 2 = 0$ ?

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Answer 1 · 2016-03-18T13:05:55

can't be factored.

$D = b^2 - 4ac = 16 + 40 = 56$
Since D is not a perfect square, this trinomial can't be factored

How do you factor 5x^2– 4x – 2 = 05x^2– 4x – 2 = 0?