How do you factor #5x^(2) - 7xy - 6y^(2)#?

1 Answer
Apr 9, 2016

Answer:

(5x + 3y)(x - 2y)

Explanation:

f(x,y) = 5x^2 - 7xy - 6y^2.= 5(x + p)(x + q)
To factor this trinomial, consider x as variable and y as a constant.
Use the new AC Method (Socratic Search)
Converted trinomial f'(x,y) = x^2 - 7xy - 30y^2 = (x + p')(x + q')
Find two quantities knowing sum (-7y) and product (-30y^2).
They are: p' = 3y and q' = - 10y --> sum (-7y) and product (-30y^2)
Back to trinomial f(x,y), #p = (p')/a = (3y)/5# and
#q = (q')/a = (-10y)/5 = -2y#.

Factored form:# f(x,y) = 5(x + (3y)/5)(x - 2y) = (5x + 3y)(x - 2y)#