How do you factor #5y^2-12y+4=0#?
Read all the clues which are given in the quadratic trinomial:
We need to find factors of
The factors of 5 and 4 must
The signs in the brackets will be
They will BOTH be
Use factors of 5 and 4 and test the cross-products:
The top row gives the factors in one bracket.
The second gives the factors in the other bracket.
Solving would lead to
(5x - 2)(x - 2)
Use the new AC Method (Socratic Search)
Method. Find p' and q' then divide them by a to get p and q.
p' and q' have same sign because ac > 0.
Factor pairs of (ac = 20) --> (2, 10)(-2, -10). This last sum is -12 = b.
Then, p' = -2 and q' = -10
Back to f(y) -->
Factor form of f(y):