How do you factor #5y^2 - 2y - 3#?
OK i'll try my best.
Think of a factorised equation as being in the form
So, what two integers multiply together to get 5? 5 and 1. So
What two integers multiply together to get -3? Well, there's four possibilities.
Which of these combinations gets you
Factor by grouping. You should get
Factor by grouping is by far the easiest factoring method I have ever encountered. First of all let me say that if you can factor a number out of the front number DO IT. Making the
Start by multiplying your
When you multiply
Next step is to make the formula to factor:
Split you middle term into
Next, put parenthesis around the first two variables and last two like so:
Now this is starting to look like something you can factor. If you did everything right you should be able to factor the two parenthesis and get the same numbers inside both:
If that is all right you can cross out one of the parenthesis and make a new one with the numbers you just factored:
That's probably a little difficult to understand but I tried sorry.
To check just foil!!