How do you factor #64+27t^3#?

1 Answer
Apr 9, 2016

Answer:

#(4 + 3t)(16 - 12t + 9t^2 ) #

Explanation:

This is a #color(blue)" sum of 2 cubes " " and factors as follows "#

# a^3 + b^3 = color(red)(|bar(ul(color(white)(a/a)color(black)((a+b)(a^2-ab+b^2)color(white)(a/a)|)))#

For # 64 + 27t^3 , " a = 4" and b = 3t " #

substituting these values into the factored form.

#rArr 64 + 27t^3 = (4 + 3t)(16 - 12t + 9t^2) #