# How do you factor 64e^4-64?

Apr 19, 2018

$64 \left({e}^{2} + 1\right) \left(e + 1\right) \left(e - 1\right)$

#### Explanation:

Factor out $64$ so that you will have

$64 \left({e}^{4} - 1\right)$

Then factor the parentheses into 2 parts.

$64 \left({e}^{2} + 1\right) \left({e}^{2} - 1\right)$

Then do it again for the 2nd set of parentheses

$64 \left({e}^{2} + 1\right) \left(e + 1\right) \left(e - 1\right)$