How do you factor #64e^4-64#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Andrew S. · Stefan V. Apr 19, 2018 Answer: #64(e^2+1)(e+1)(e-1)# Explanation: Factor out #64# so that you will have #64(e^4-1)# Then factor the parentheses into 2 parts. #64 (e^2+1)(e^2-1)# Then do it again for the 2nd set of parentheses #64(e^2+1)(e+1)(e-1)# Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 235 views around the world You can reuse this answer Creative Commons License