How do you factor 64x^2 + 112x + 49?

1 Answer
Jun 8, 2016

(7x+8)^2

Explanation:

The key to factoring this is noticing that the first and last terms are both squared terms:

  • 64x^2=(8x)^2
  • 49=(7)^2

This is a good indicator that the expression is a perfect square binomial, which comes in the form:

(a+b)^2=(a+b)(a+b)=a^2+2ab+b^2

Here, a=8x and b=7, as indicated to us by the 64x^2 and 49 terms. However, we still have to determine whether or not the middle term 112x is equal to 2ab.

2ab=2(8x)(7)=112x

Since 2ab does equal 112x, we know that this is a perfect square binomial.

64x^2+112x+49=(7x+8)^2