How do you factor #64x^2 + 112x + 49#?
1 Answer
Jun 8, 2016
Explanation:
The key to factoring this is noticing that the first and last terms are both squared terms:
#64x^2=(8x)^2# #49=(7)^2#
This is a good indicator that the expression is a perfect square binomial, which comes in the form:
#(a+b)^2=(a+b)(a+b)=a^2+2ab+b^2#
Here,
#2ab=2(8x)(7)=112x#
Since
#64x^2+112x+49=(7x+8)^2#