# How do you factor 64x^3-27?

$\implies \left(4 x - 3\right) \left(16 {x}^{2} + 12 x + 9\right)$
$\implies {\left(4 x\right)}^{3} - {3}^{3}$
$\implies \left(4 x - 3\right) \left({\left(4 x\right)}^{2} + 4 x \cdot 3 + {3}^{2}\right)$
$\implies \left(4 x - 3\right) \left(16 {x}^{2} + 12 x + 9\right)$