How do you factor #6b^2 + b - 2#?

1 Answer
May 31, 2018

Answer:

#(2b-1)(3b+2)#

Explanation:

#"using the a-c method to factor the quadratic"#

#"the factors of the product "6xx-2=-12#

#"which sum to + 1 are - 3 and + 4"#

#"split the middle term using these factors"#

#6b^2-3b+4b-2larrcolor(blue)"factor by grouping"#

#=color(red)(3b)(2b-1)color(red)(+2)(2b-1)#

#"take out the "color(blue)"common factor "(2b-1)#

#=(2b-1)(color(red)(3b+2))#

#6b^2+b-2=(2b-1)(3b+2)#