# How do you factor 6t^2 + 13t – 63?

$6 {t}^{2} + 13 t - 63 = \left(3 t - 7\right) \left(2 t + 9\right)$[
$6 {t}^{2} + 13 t - 63 = 6 {t}^{2} + 27 t - 14 t - 63 = 3 t \left(2 t + 9\right) - 7 \left(2 t + 9\right) = \left(3 t - 7\right) \left(2 t + 9\right)$[Ans]