How do you factor $6x^2 - 18x + 12$ ?

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Answer 1 · 2015-06-10T20:07:51

$6x^2-18+12=6(x-1)(x-2)$

$6x^2-18+12$

Factor out the GCF $6$ .

$6(x^2-3x+2)$

Factor $x^2-3x+2$ .

Find two numbers that when added are equal to $-3$ , and when multiplied are equal to $2$ .

The numbers $-1$ and $-2$ fit the criteria.

$x^2-3x+2=(x-1)(x-2)$

$6x^2-18+12=6(x-1)(x-2)$

How do you factor 6x^2 - 18x + 126x^2 - 18x + 12?