# How do you factor 6x^2 - 18x + 12?

Jun 10, 2015

$6 {x}^{2} - 18 + 12 = 6 \left(x - 1\right) \left(x - 2\right)$

#### Explanation:

$6 {x}^{2} - 18 + 12$

Factor out the GCF $6$.

$6 \left({x}^{2} - 3 x + 2\right)$

Factor ${x}^{2} - 3 x + 2$.

Find two numbers that when added are equal to $- 3$, and when multiplied are equal to $2$.

The numbers $- 1$ and $- 2$ fit the criteria.

${x}^{2} - 3 x + 2 = \left(x - 1\right) \left(x - 2\right)$

$6 {x}^{2} - 18 + 12 = 6 \left(x - 1\right) \left(x - 2\right)$