How do you factor #6x^2=8x+8#?

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Answer 1 · 2018-04-21T18:57:10

The factored form is #(3x+2)(x-2)=0#.

First, put everything on one side of the equation:

#6x^2=8x+8#

#6x^2-8x=8#

#6x^2-8x-8=0#

Factor out a #2#:

#2(3x^2-4x-4)=0#

#2(3x^2-6x+2x-4)=0#

#2(3x(x-2)+2x-4)=0#

#2(3x(x-2)+2(x-2))=0#

#2(3x+2)(x-2)=0#

That's the factored polynomial. Hope this helped!