How do you factor 6x^3+10x^2-326x3+10x2−32?

1 Answer
bp
Sep 30, 2015

2 (x-4/3)(3x^2 +8x +12)2(x−43)(3x2+8x+12)

Explanation:

After taking out 2 as a common factor it becomes 2(3x^3 +5x^2 -16)2(3x3+5x2−16)

In this 3rd degree polynomial, the product of its roots (zeros) would be -16/3−163. Try x=4/3x=43, it is found that it is on of the roots. Hence (x-4/3)(x−43) would be a factor. Now carry out long or synthetic division of the polynomial by (x-4/3)(x−43) to have 3x^2 + 8x+123x2+8x+12 as a quotient.

The required factorisation would be thus 2 (x-4/3)(3x^2 +8x +12)2(x−43)(3x2+8x+12)

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