# How do you factor 6x^3+21x^2?

We can factor a $3 {x}^{2}$ out of this expression as:
$\left(3 {x}^{2} \cdot 2 x\right) + \left(3 {x}^{2} \cdot 7\right) \implies$
$3 {x}^{2} \left(2 x + 7\right)$