How do you factor $6x^3-48$ ?

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Answer 1 · 2018-05-03T23:31:39

$6(x-2)(x^2 + 2x + 4)$

To factor, we have to find the GCF, or Greatest Common Factor. This means the largest factor that both expressions have.

Therefore, the GCF is $6$ . So when we factor it becomes:
$6(x^3 - 8)$

We can still factor this further.

$(x^3 - 8)$ is in the form $a^3 - b^3$ , which factors down to $(a-b)(a^2 + ab + b^2)$

Therefore, that becomes:
$(x-2)(x^2 + 2x + 4)$

So the completely factored answer is:
$6(x-2)(x^2 + 2x + 4)$

Hope this helps!

How do you factor 6x^3-486x^3-48?