How do you factor 6x^3-x^2+17=2x^2+47?

1 Answer
Apr 20, 2018

x^2 (2x - 1) = 10

Explanation:

Factor
6x^3−x^2+17=2x^2+47

1) Subtract 2x^2 from both sides to get all the x terms together
6x^3 - x^2 - 2x^2 + 17 = 47

2) Subtract 17 from both sides to get all the constants on the same side
6x^3 - x^2 - 2x^2 = 47 - 17

3) Combine like terms
6x^3 - 3x^2 = 30

4) Divide all the terms on both sides by 3 to reduce the terms
2x^3 - x^2 = 10

5) Factor out x^2
x^2 (2x - 1) = 10