# How do you factor 6x^3-x^2+17=2x^2+47?

Apr 20, 2018

x^2 (2x - 1) = 10

#### Explanation:

Factor
6x^3−x^2+17=2x^2+47

1) Subtract $2 {x}^{2}$ from both sides to get all the $x$ terms together
$6 {x}^{3} - {x}^{2} - 2 {x}^{2} + 17 = 47$

2) Subtract $17$ from both sides to get all the constants on the same side
$6 {x}^{3} - {x}^{2} - 2 {x}^{2} = 47 - 17$

3) Combine like terms
$6 {x}^{3} - 3 {x}^{2} = 30$

4) Divide all the terms on both sides by $3$ to reduce the terms
$2 {x}^{3} - {x}^{2} = 10$

5) Factor out ${x}^{2}$
x^2 (2x - 1) = 10