# How do you factor 6x-x^3-x^2?

$6 x - {x}^{3} - {x}^{2} = - x \left(x + 3\right) \left(x - 2\right)$
Separate out a common factor $- x$ and rearrange in descending order of powers of $x$. Then find a pair of numbers with product $6$ and difference $1$. The pair $3$, $2$ works, so we find:
$6 x - {x}^{3} - {x}^{2} = - x \left({x}^{2} + x - 6\right) = - x \left(x + 3\right) \left(x - 2\right)$