How do you factor #6y^5 + 32y^4 + 32y^3#?
Factor the trinomial in parentheses by the new AC Method (Yahoo, Google Search)
Converted trinomial: y^2 + 16y + 48.
Compose factor pairs of (a.c) = 48: (2, 24)(3, 16)(4, 12). OK
p' = 4 and q' = 12 --> p = 4/3 and q = 12/3 = 4
f(y) = 2y^3(3y + 4)(y + 4).
In this polynomial expression I notice that all the degrees of y are greater than 3, so I decide to "simplify" by
Now I can even try to factor the part
We can state that:
So the initial polinomial expression can be rewritten as this: