# How do you factor #7ab^2 - 77ab + 168a#?

##### 1 Answer

Apr 9, 2018

#### Answer:

#### Explanation:

Given:

#7ab^2-77ab+168a#

Note that all of the terms are divisible by

#7ab^2-77ab+168a = 7a(b^2-11b+24)#

To factor the remaining quadratic we can find a pair of factors of

#b^2-11b+24 = (b-8)(b-3)#

So:

#7ab^2-77ab+168a = 7a(b-8)(b-3)#