# How do you factor 7p^2 + 51p + 14?

$f \left(x\right) = 7 {x}^{2} + 51 x + 14$ = (x - p)(x - q). Use the new AC Method.
Converted trinomial: $y ' = {x}^{2} + 51 x + 98$ = (x - p')(x - q').
Then, $p = \frac{p '}{a} = \frac{2}{7}$, and $q = \frac{q '}{a} = \frac{49}{7} = 7.$
Check by developing: $y = 7 {x}^{2} + 49 x + 2 x + 14$.. OK