How do you factor #7x^2 -45#?

1 Answer
Antoine
May 2, 2015

The answer is #(sqrt(7)x+sqrt(45))(sqrt(7)x−sqrt(45))# .

#(7x^2-45)# fits the pattern of the difference of squares in which #(a^2−b^2)=(a+b)(a−b)# .

The factorization of #(7x^2-45)=((sqrt(7)x)^2−(sqrt(45))^2) #

Here #a=sqrt(7)x # , # b=sqrt(45)#

So the factorization is #(sqrt(7)x+sqrt(45))(sqrt(7)x−sqrt(45))#

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