How do you factor #7x^2 - 9x - 10#?
Let's start by finding the zeroes of the trynomial:
Since a trynomial can be factorized by the formula:
(7x + 5)(x - 2)
Use the new AC method to factor trinomials (Socratic Search)
Find p' ans q' knowing they have opposite sign since ac < 0.
Factor pairs of (ac = -70) --> ...(-5, 14)(5, - 14). This sum is (-9 = b). Then, p' = 5 and q' = -14.
Back to original y -->