How do you factor #7x+28x^2-35x^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer iceman · EZ as pi Feb 16, 2017 Answer: #-7x(5x+1)(x-1)# Explanation: #7x+28x^2-35x^3# => factor GCF: Note that dividing by #-7x# makes a positive #x^2# term. #-7x(5x^2-4x-1)# #-7x(5x^2-5x+x-1)# #-7x[5x(x-1)+(x-1)]# #-7x(x-1)(5x+1)# Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than ... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 330 views around the world You can reuse this answer Creative Commons License