How do you factor 7x+28x^2-35x^3?

Feb 16, 2017

$- 7 x \left(5 x + 1\right) \left(x - 1\right)$

Explanation:

$7 x + 28 {x}^{2} - 35 {x}^{3}$ => factor GCF:

Note that dividing by $- 7 x$ makes a positive ${x}^{2}$ term.

$- 7 x \left(5 {x}^{2} - 4 x - 1\right)$
$- 7 x \left(5 {x}^{2} - 5 x + x - 1\right)$
$- 7 x \left[5 x \left(x - 1\right) + \left(x - 1\right)\right]$
$- 7 x \left(x - 1\right) \left(5 x + 1\right)$