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How do you factor $7 x^{3} - 4 x^{2} + 8 x$ $7x^3-4x^2+8x$ ?

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Jun 5, 2015

$7 x^{3} - 4 x^{2} + 8 x$ $7x^3-4x^2+8x$
$XXXX$ $color(white)("XXXX")$ $= x (7 x^{2} - 4 x + 8)$ $= x(7x^2-4x+8)$

Checking the discriminant of the second factor reveals that there are no Real factors for this term.

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