How do you factor # 7y^2+19y+10 #?
then we need to find factors
The only integer factors of
The (non-negative) integer factors of
This gives us 4 possible combinations to check and we find:
Ans: (7x + 5)(x + 2)
I use the new AC Method.
p' and q' have same sign (Rule of signs)
Factor pairs of 70 --> (2, 35)(5, 14). This sum is 19 = b.
Then, p' = 5 and q' = 14.
Factored form: y = 7(y + 5/7)(y + 2) = (7y + 5)(y + 2).