How do you factor #8a + 6ax - 21x - 28#?

1 Answer
Sep 2, 2016

Answer:

#8a+6ax-21x-28 = (2a-7)(3x+4)#

Explanation:

This will factor by grouping once we swap the first two terms:

#8a+6ax-21x-28 = 6ax+8a-21x-28#

#color(white)(8a+6ax-21x-28) = (6ax+8a)-(21x+28)#

#color(white)(8a+6ax-21x-28) = 2a(3x+4)-7(3x+4)#

#color(white)(8a+6ax-21x-28) = (2a-7)(3x+4)#