How do you factor #8t^3 -27#?

1 Answer
Jun 10, 2016

Answer:

#(2t-3)(4t^2+6t+9)#

Explanation:

This is a #color(blue)"difference of cubes"# which is factorised.

#color(red)(|bar(ul(color(white)(a/a)color(black)(a^3-b^3=(a-b)(a^2+ab+b^2))color(white)(a/a)|)))#

here #8t^3=(2t)^3rArra=2t#

and #27=(3)^3rArrb=3#

Substitute these into the right side gives.

#8t^3-27=(2t-3)(4t^2+6t+9)#