How do you factor #8w^7+18w^6-18w^5#?
Factor y by the new AC Method (Socratic Search)
Converted trinomial y' = w^2 + 9w - 36 = (x + p')(x + q').
p' and q' have opposite signs because ac < 0. Compose factor pairs of (ac = -36)-->...(-3, 12). This sum is 9 = b. Then p' = -3 and q' = 12.
Back to trinomial y,
Factored form of y:
Factored form of f(w):