# How do you factor 8x^3+1?

In general ${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
$8 {x}^{3} + 1$
$= {\left(2 x\right)}^{3} + {\left(1\right)}^{3}$
$= \left(2 x + 1\right) \left(4 {x}^{2} - 2 x + 1\right)$