How do you factor $8 x^{3} - 125$ $8x^3-125$ ?

Question

How do you factor $8 x^{3} - 125$ $8x^3-125$ ?

1 Answer

Impact of this question

18966 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-24T18:34:34

$(2 x - 5) (4 x^{2} + 10 x + 25)$ $(2x-5)(4x^2+10x+25)$

Explanation:

Factoring difference of cubes ( $a^{3} - b^{3}$ $a^3-b^3$ ): $(a - b) (a^{2} + a b + b^{2})$ $(a-b)(a^2+ab+b^2)$

Here, $a$ $a$ is $2 x$ $2x$ because the cube root of 8 is 2 and the cube root of $x^{3}$ $x^3$ is $x$ $x$ , $b$ $b$ is 5 because the cube root of 125 is 5.

Plug the numbers in:

$(2 x - 5) ({(2 x)}^{2} + 2 x \cdot 5 + 5^{2})$ $(2x-5)((2x)^2+2x*5+5^2)$

$(2 x - 5) (2^{2} x^{2} + 10 x + 25)$ $(2x-5)(2^2x^2+10x+25)$

$(2 x - 5) (4 x^{2} + 10 x + 25)$ $(2x-5)(4x^2+10x+25)$

Science

Math

Humanities

... and beyond

How do you factor $8 x^{3} - 125$ $8x^3-125$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 8x^3-1258x3−1258x^3-125?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $8 x^{3} - 125$ $8x^3-125$ ?