Question

How do you factor `8x^3 - 3x^2 + 16x - 6`?

Answer 1

`(x^2 + 2)(8x - 3)`

Explanation:

Factor by grouping:
`y = 8x^3 + 16x - 3x^2 - 6`
`y = 8x(x^2 + 2) - 3(x^2 + 2)`
`y = (x^2 + 2)(8x - 3)`
You can put further with complex numbers -->
`y = (x - isqrt2)(x + isqrt2)(8x - 3)`