# How do you factor 8x^3-8?

$8 {x}^{3} - 8 = 8 \left({x}^{3} - 1\right) = 8 \left({x}^{3} - {1}^{3}\right)$
$= 8 \left(x - 1\right) \left({x}^{2} + x + 1\right)$
${a}^{3} - {b}^{3} = \left(a - b\right) \left({a}^{2} + a b + {b}^{2}\right)$