How do you factor #8x^3+x^2+56x+7#?

1 Answer
Apr 18, 2018

Answer:

the answer is #(x^2+7)(8x+1)#

Explanation:

well since it's like this, all you have to do it group them since it's in a four term already. so:#(8x^3+x^2)+(56x+7)# and now take out from first equation #x^2(8x+1)# and now the second #7(8x+1)# make sure the inside parenthesis matches and you got your answer