# How do you factor 8x^3+x^2+56x+7?

the answer is $\left({x}^{2} + 7\right) \left(8 x + 1\right)$
well since it's like this, all you have to do it group them since it's in a four term already. so:$\left(8 {x}^{3} + {x}^{2}\right) + \left(56 x + 7\right)$ and now take out from first equation ${x}^{2} \left(8 x + 1\right)$ and now the second $7 \left(8 x + 1\right)$ make sure the inside parenthesis matches and you got your answer