# How do you factor 8x^4-128?

$8 {x}^{4} - 128 = 8 \cdot \left({x}^{4} - 16\right) = 8 \cdot \left({x}^{4} - {2}^{4}\right) = 8 \cdot \left({x}^{2} - 4\right) \cdot \left({x}^{2} + 4\right) = 8 \cdot \left(x - 2\right) \cdot \left(x + 2\right) \cdot \left({x}^{2} + 4\right)$