How do you factor #8x^6 + 7x^3 - 1#?
This is in the form of a quadratic because.
Find the factors of 8 (and 1) which subtract to give 7
The signs will be different (because of -1)
There must be more positives (because of +7)
The factors of -1 can only be +1 and -1
Place the 8 and the 1 so that we will get +8 and -1. when we multiply.
Reverse to x we have that
Hence finally we get