How do you factor $8 x y - 10 y + 36 x - 45$ $8xy - 10y + 36x - 45$ ?

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How do you factor $8 x y - 10 y + 36 x - 45$ $8xy - 10y + 36x - 45$ ?

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Answer 1 · 2016-05-12T00:05:59

$(2 y + 9) (4 x - 5)$ $(2y+9)(4x-5)$

Explanation:

Factor by grouping:

$8 x y - 10 y + 36 x - 45$ $8xy-10y+36x-45$

$= (8 x y - 10 y) + (36 x - 45)$ $=(8xy-10y)+(36x-45)$

$= 2 y (4 x - 5) + 9 (4 x - 5)$ $=2y(4x-5)+9(4x-5)$

$= (2 y + 9) (4 x - 5)$ $=(2y+9)(4x-5)$

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How do you factor $8 x y - 10 y + 36 x - 45$ $8xy - 10y + 36x - 45$ ?

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How do you factor $8 x y - 10 y + 36 x - 45$ $8xy - 10y + 36x - 45$ ?