How do you factor $8y^2 + 17y + 9$ ?

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Answer 1 · 2015-08-08T15:20:49

Factor: $f(y) = 8y^2 + 17y + 9$

Discriminant: D = b^2 - 4ac = 289 - 288 = 1.
Since D is not a perfect square, the function can't be factored.

How do you factor 8y^2 + 17y + 98y^2 + 17y + 9?