How do you factor $8y^3+ 1$ ?

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Answer 1 · 2018-03-09T06:07:11

$(2y+1)(4y^2-2y+1)$

Given, $8y^3+1$
$rArr (2y)^3+(1)^3$
$rArr (2y+1)^3-3.2y.1(2y+1)$
$rArr (2y+1)[(2y+1)^2-6y]$
$rArr (2y+1)[4y^2+4y+1-6y]$
$rArr (2y+1)(4y^2-2y+1)$

How do you factor 8y^3+ 18y^3+ 1?