How do you factor #9t^3+18t-t^2-2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. Jun 3, 2015 #9t^3+18t-t^2-2 = (9t^3+18t)-(t^2+2)# #=9t(t^2+2)-(t^2+2)# #=(9t-1)(t^2+2)# Since #t^2+2 > 0# for all #t in RR#, it has no linear factors with real coefficients. So our factorization is complete. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1326 views around the world You can reuse this answer Creative Commons License