How do you factor #9x^2+4y^2#?

1 Answer
May 31, 2017

Answer:

I think the only operation u can do with this polynome is writing it a a sum of squares and 'compleating the square'.

Explanation:

You can see #9x^2+4y^2#as #(3x)^2+(2y)^2#.
Given the formula #a^2+b^2+2ab=(a+b)^2# with #a=3x# and #b=2y# you have #2ab=(2*3*2)xy=12xy# so u can add and subtract it to have:
#=(3x)^2+(2y)^2+12xy-12xy=[(3x)^2+(2y)^2+12xy]-12xy=(3x+2y)^2-12xy#
This is not really a smart move in this case but i think it's the only operatio you can do with this polinom.