How do you factor $9xy^2 - 16x$ ?

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Answer 1 · 2016-11-06T23:20:31

Please see the explanation for steps leading to the factors:

$x(3y - 4)(3y + 4)$

$9xy^2 - 16x =$

$x(9y^2 - 16) =$

$x(3y - 4)(3y + 4)$

How do you factor 9xy^2 - 16x9xy^2 - 16x?