How do you factor 9y^2 - 1 ? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Candy Mar 19, 2018 9y^2-1=(3y+1)(3y-1) Explanation: 9y^2-1 =(3y)^2-(1)^2 Using the identity a^2-b^2=(a+b)(a-b), You can further simplify ((3y)^2-(1)^2) as (3y)^2-(1)^2=(3y+1)(3y-1) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 6162 views around the world You can reuse this answer Creative Commons License