# How do you factor #9y^2+18y+8#?

##### 2 Answers

May 9, 2015

Looking for

reveals the solution:

May 9, 2015

I use the new AC Method (Google, Yahoo Search) to factor:

f(x) = 9y^2 + 18y + 8. = (y - p)(y - q)

Converted trinomial: f'(y) = y^2 + 18y + 72 = (y -p') (y - q') with

(a.c = 9.(8) = 72.

Compose factor pairs of ac = 72. Proceed: (1, 72)(2, 36)...(6, 12).OK

f(y) = (y + 2/3)(y + 4/3) = (3y + 2)(3y + 4)