How do you factor #9z^2 + 27z -az - 3a#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Don't Memorise May 8, 2015 We can factor this expression by making groups of 2 terms: #(9z^2 + 27z) -(az + 3a)# #9z# is common to both the terms in the first group, and #a# is common to both the terms in the second group # = 9z(z+3) - a(z+3)# #z+3# is common to both the terms now #= color(green)((z+3)(9z-a)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1379 views around the world You can reuse this answer Creative Commons License