How do you factor #a^2 − 36#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Don't Memorise May 4, 2015 #a^2 - 36# can be written as #a^2 - 6^2# this is of the form: #a^2 - b^2 = ( a + b) (a -b ) # so , # a^2 - 6^2= (a +6) (a - 6) # the factorized form of #a^2 - 36# is: #(a +6) (a - 6)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 4243 views around the world You can reuse this answer Creative Commons License