How do you factor # a(a+6)+7(a+6)#?

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Answer 1 · 2016-04-23T08:35:38

#a^2 + 6a + 7a + 42#

#a^2 + 13a + 42#

First you need to expand out the brackets by multiplying the outer number with the inner two numbers separately. Now we'll do #a(a+6)#.

#a xx a = a^2#

#a xx 6 = 6a#

That's the first set of brackets expanded. Now for the second pair of brackets, where we do the same thing.

#7 xx a = 7a#

#7 xx 6 = 42#

Collect the like terms.

#7a + 6a = 13a#

Add the others.

#a^2 + 13a + 42#

You cannot solve this equation because the value of #a# is unknown.